Question

A proud deep-sea fisherman hangs a 64.0-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.135 m.

(a) Find the force constant of the spring.
N/m

The fish is now pulled down 5.75 cm and released.

(b) What is the period of oscillation of the fish?
s

(c) What is the maximum speed it will reach?
m/s

Answer 1

given the spring mass is negligible

the mass of the fish hanging = 64kg

(a) Find the force constant of the spring.
N/m

The fish is now pulled down 5.75 cm and released.

(b) What is the period of oscillation of the fish?
s

(c) What is the maximum speed it will reach?
m/s

mass of fish m=65kg then , dx=0.135m, A=0.0575

Since F=k * dx=mg ->

we got

k=mg/(dx)

force constant K= 64*9.8/0.0575

the spring constant F= 10907.82

b) w=sqrt(k/m)=sqrt(g/dx)

W= sqrt (9.8/0.135)

W = sqrt(72.59)

W= 8.520

c) vmax=Aw=Asqrt(g/dx)

Vmax= AW =0.0575*8.520

Vmax= 0.4899m/s