Question

Under some circumstances, a star can collapse into an extremely
dense object made mostly of neutrons and called a |
Part A If the original star rotated once in 25 days, find the angular speed of the neutron star. Express your answer using two significant figures. |

Answer #1

Let us find out the initial angular speed off the star.

It rotated once in 25 days, so angular velocity is

Now, angular momentum of the system must be conserved.

Modelling the star as a sphere of mass M and initial and final radius as R1 and R2 we must have

is the final angular velocity

Putting the values,

This is the angular speed of the star.

Neutron Star Physics
Under some circumstances, an ordinary star can undergo
gravitational collapse into an extremely dense object made mostly
of neutrons. This type of star is called a "neutron star". A
neutron star has a mass density roughly 1014 times
larger than that of ordinary solid matter.
Suppose we represent an ordinary star as a uniform solid rigid
sphere, both before and after the collapse. The original star's
initial radius is 7.0 x 105 km (comparable to the size...

A star may collapse into an extremely dense body (called neutron
star ) composed predominantly of neutrons. This can happen when
massive stars die in supernovas and their cores collapse. Represent
the star as a uniform solid sphere both before and after the
collpase. Assume no astronomical bodies are in the vicinity of the
star, so no forces or torques are exerted on the star. The star’s
initial radius was 9.45 × 108 m, its final radius is 15200 m,...

Suppose a star the size of our Sun
(r=7.0*105 km), but with mass
6.0 times as great, were rotating at a speed of 1.0 revolution
every 10 days. If it were to undergo gravitational collapse to a
neutron star of radius 10 km, losing 2/3 of its mass in the
process, what would its rotation period be in
μs? Assume the star is a uniform sphere
at all times. Assume also that the thrown-off mass carries off no
angular momentum....

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