Question

A 10-Hz generator produces a peak emf of 40 V

Determine the emf at the following times: 0.025 s, 0.050 s, 0.075 s, and 0.100 s

When I tried the problem I answered with 40,0.063,-40,-0.127 but it says its wrong

Answer #1

Given:

f = 10 Hz

V_{o} = 40 V

= 2f = 2 (10) = 62.8 rad/s

or = 20

Therefore: general form is: V = V_{o} sin t

Hence: V = 40 sin(20t)

when t = 0.025

V = 40 sin (2*3.14* 10 *0.025)

( use Calculator in radains)

V = 40 Volts

V at t = 0.05 is

V = 40 sin ( 2*3.14* 10 * 0.05)

V = 0.063 Volts

at t = 0.075 secs

V = 40 sin ( 2*3.14 * 10 * 0.075)

V = -40 Volts

at t = 0.1 secs

V = 40 sin( 2*3.14 * 10 * 0.1)

V = -0.127 Volts

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