Question

A) An object is placed in front of a concave mirror whose radius of curvature is R. What is the greatest distance behind the mirror that the image can be formed? Explain.

B) Light consisting of a mixture of red and blue light enters a 40°, 70°, 70° prism along a line parallel to the side opposite the 40° vertex. The index of refraction of the prism material for blue light is 1.530, and for red light, it is 1.525. What is the angle between the two emerging beams of light?

please solve & explain!

Answer 1

So we know conacave mirror is a converging in which rays converges ahead of mirror when object is placed is after the focal point.

But when we place object at a distance less than focal Length than image form virtually behind the lens and Maximum distance upto which image can form is can be calculated from mirror formula

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So when u tends to f from right side then we get

2) so deflection for a ray when Passing through prism is given by

So net angle between two different refractive indices of light we get,

So A = 40°

We get, net angle