Question

One lump of clay traveling at 35 m/s overtakes a second lump traveling at 13.0 m/s....

One lump of clay traveling at 35 m/s overtakes a second lump traveling at 13.0 m/s. After collision, they are stuck together. What is their common velocity?
(a)27.7 s , (b)35.6 s , (c)40.1 s , (d)56.7 s .
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Answer #1

Let the mass of first lump be m1, that of second be m2 and their velocity after collision be v.

Given, v1 = 35 m/s, v2 = 13 m/s.

By law of conservation of angular momentum,

If m1 = m2 = m

Note- The question asked velocity but you have provided options for time.

Note- The masses of the two clay lumps were not given, so I have taken a case for them to be equal. However, if the masses are different then you can use equation (1) to find the required velocity by plugging in the data for respective velocities and masses of both lumps.

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