Question

A "shaker table" is a device on which you very securely mount an
object and shake it to see if it comes apart under the acceleration
due to the shaking. It is widely used to test electronic components
to be launched into space to see if they can withstand the
acceleration forces that are involved in the launch. The shaking is
usually simple harmonic. In operation, such a shaker is started at
zero frequency and, while the amplitude is fixed, the frequency is
increased. If the amplitude of the shaker is set to 1.80 cm, at
what oscillation frequency is the maximum acceleration of the
object under test equal to 10.40 *g*'s? (One *g* is
9.8 m/s^{2}). Give your answer in Hz.

Answer #1

As mentioned in the problem -

Amplitude of the shaker, A = 1.80 cm = 0.018 m

Maximum acceleration of the object under test -

a = 10.40g = 10.40 * 9.8 = 101.92 m/s^2

Suppose, angular velocity of the object = w

So, in the case of simple harmonic motion -

Maximum acceleration is given as,

a = A*w^2

=> 101.92 m/s^2 = 0.018 m * w^2

=> w^2 = 101.92 / 0.018

=> w = 75.25 rad/s

So, the oscillation frequency (f) = w / (2*pi) = 75.25 / (2*3.141) = 12.0 Hz (Answer)

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 8 minutes ago

asked 12 minutes ago

asked 20 minutes ago

asked 21 minutes ago

asked 26 minutes ago

asked 35 minutes ago

asked 58 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago