Question

You toss a 0.90kg M-80 into the sky with a velocity 3.9m/s i^+ 9.8m/s j^ at t= 0s . At t= 0.60s the M-80 explodes into two unequal chunks of m1= 0.3kg and m2= 0.6kg . Ignore any air resistance.

What is the x -component of the first chunk's velocity immediately after the explosion if the second chunk's velocity immediately after the explosion is −12m/s i^+ 33.8m/s j^ ?

Answer #1

apply momentum conservation

=

0.9* ( 3.9 i +9.8 j ) = 0.3 *( ) + 0.6* ( -12 i +33.8 j )

0.3 *( ) = 0.9* ( 3.9 i +9.8 j ) - 0.6* ( -12 i +33.8 j )

= ( 0.9*3.9+0.6*12) i +( 0.9*9.8 -0.6*33.8)j

0.3 *( ) = 10.71 i -11.46 j

= 3.57 i -3.82 j

x -component of the first chunk's velocity = **35.7 m/s
answer **

in adition

y -component of the first chunk's velocity = -3.82 m/s

A 32-kg shell is fired from a gun with a muzzle velocity 80 m/s
at 50o above the horizontal. At the top of the
trajectory, the shell explodes into two fragments of equal mass.
One fragment, whose speed immediately after the explosion is zero,
falls vertically. Calculate the range of the other fragment,
assuming level terrain.

You toss a truck into the air at an angle of theta above the
horizontal so that it will travel in an arc... off the side of a
cliff - in the middle of winter. After you throw it, you know the
following:
the horizontal component of the truck's velocity is 16.4
m/s.
the vertical component of the truck's velocity is 16.9
m/s.
The truck is in free fall (no air resistance) while it is in
the air.
What is...

(hrw8c9p15) A shell is fired from a gun with a muzzle velocity of
39 m/s, at an angle of 60° with the horizontal. At the top
of the trajectory, the shell explodes into two fragments of equal
mass (see the figure). One fragment, whose speed immediately after
the explosion is zero, falls vertically. How far from the gun does
the other fragment land, assuming that the terrain is level and
that the air drag is negligible?

A bullet shot from a small firearm has an initial velocity
v0 of 52 m/s at an angle theta = 42 with respect to the horizontal.
At the maximum trajectory (max height), we observe that, the bullet
explodes into two small pieces both of which are of equal mass. One
fragment immediately after the explosion is therefore
zero m/s and it falls vertically.
How long (in seconds) does it take the shell to reach this
point trajectory (max height)?
What is...

A relativistic particle is moving with a velocity of (3.0x105
m/s) i + (4.0x106 m/s) j. Another relativistic particle which is 4
times massive than the first particle is moving with velocity of
(3.0x105 m/s) i - (1.0x106 m/s) j. The particles collide and the
collision is perfectly inelastic.
a. What are the velocities of the particles just after the
collision?
b. What percent of energy is lost just after the collision?

A shell is shot with an initial velocity of 21 m/s, at an angle
of 62 degrees above the horizontal. How long does it take for the
shell to get to the top of its trajectory? At the top of the
trajectory, the shell explodes into two fragments of equal mass, as
shown in the figure below. One fragment, whose speed immediately
after the explosion is zero, falls vertically. How far from the gun
does this fragment land, assuming that...

A 4.0 kg projectile is launched into the air with an initial
velocity of 15 m/s at an angle of 30° above the horizontal. When
the projectile reaches its maximum height it explodes, splitting in
two parts, one of mass 3.0 kg and one of mass 1.0 kg. Assume the
explosion was essentially instantaneous.
Determine the maximum height of the projectile using energy.
After the explosion, if the 1.0 kg mass is moving at 1/2 the
speed it was right...

A relativistic particle is moving with a velocity of (3.0x10^5
m/s) i + (4.0x10^6 m/s) j. Another relativistic particle which is 4
times massive than the first particle is moving with velocity of
(3.0x10^5 m/s) i - (1.0x10^6 m/s) j. The particles collide and the
collision is perfectly inelastic.
What are the velocities of the particles just after the
collision?
What percent of energy is lost just after the collision?

A 14-kg shell is fired from a gun with a muzzle velocity 100 m/s
at 42o above the horizontal. At the top of the trajectory, the
shell explodes into two fragments of equal mass. One fragment,
whose speed immediately after the explosion is zero, falls
vertically. Calculate the range of the other fragment, assuming
level terrain.

A particle of mass m1 = 1.32 kg with an
initial velocity v1 = 4.56 m/s
has a completely inelastic collision with a second particle of mass
m2 = 3.68 kg with an initial velocity
v2 = 3.06 m/s. What is the
velocity of the combined particles immediately after the collision?
(Express your answer in vector form.)

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 11 minutes ago

asked 24 minutes ago

asked 25 minutes ago

asked 25 minutes ago

asked 41 minutes ago

asked 44 minutes ago

asked 47 minutes ago

asked 47 minutes ago

asked 53 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago