The scale of a spring balance that reads from 0 to 42.1 kg is 10.0 cm long. A package suspended from the balance is found to oscillate vertically with a frequency of 2.87 Hz. (a) What is the spring constant? (b) How much does the package weigh?
a )
given m = 42.1 kg ,
x = 10 cm = 0.1 m
the weight is " W "
W = m g
W = 42.1 X 9.8
W = 412.58 N = F
the spring constant i s" K "
K = F / x
K = 412.58 / 0.1
K = 4125.8 N/m
the spring constant is K = 4125.8 N/m
b )
f = 2.87 Hz
the frequency f = ( 1/2 ) ( K/m )1/2
then rewriting for m is
m = K / 4 2 f2
m = 4125.8 / 4 X 3.142 X 2.872
m = 12.7 kg
then the the package weight is W = m g
W = 12.7 X 9.8
W = 124.466 N
the package weight is W = 124.466 N
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