Question

An aluminum sphere is 8.85 cm in diameter.

What will be its change in volume if it is heated from 30 ∘C to 200 ∘C?

Express your answer using two significant figures.

answer in cm^3

Answer 1

V₀ = 4/3*pi*r^3 = 4/3*pi*( 0.0885/2)^3 =3.62934651 × 10^-4 m³

change in volume  

β = 3*α = 75*10^-6

ΔV = βΔTV₀ = 75*10^-6*( 200-30) *3.62934651 × 10^-4 =4.62741680025 × 10^-6

ΔV =4.62741680025 × 10^-6

ΔV = 4.62741680025 × 10^-6

change in volume =4.62741680025 × 10^-6 m³

change in volume =   4.63 cm^3 answer

****************************************************************************
Goodluck for exam Comment in case any doubt, will reply for sure..