Question

Two students are running in the same direction on a circular path (assume that they start the race at the same point and same time). The length of the circular path is 198 m . One student runs with a constant velocity of 5.20 m/s and second student runs with a constant velocity of 6.20 m/s .

-When will the fast one tour the slower one?

-How far from the starting point will the slower one have run?

-How far from the starting point will the fast one have run?

Answer 1

Solution: Given:- Length of the circular path, S =198m, velocity of student1, v₁ =5.20m/s, velocity of student2, v₂ = 6.2m/s.

Calculate the time taken for both of them to meet each other along the circular path.

Time taken = S / (v₁ + v₂ )

Time taken = 198 / (5.2 + 6.2)

Time taken = 198 / 11.4

Time taken = 17.368 seconds.

The distance covered by student1 during this time period from the starting point is given by:

Distance, s₁ = 17.368 x 5.2

Distance, s₁ = 90.3 m . Ans

The distnace covered by student2 during this time period from the starting point is given by:

Distance, s₂ = 17.368 x 6.2

Distance, s₂ = 107.68 m . Ans