Question

A converging lens (*f*_{1} = 24.0 cm) is located
56.0 cm to the left of a diverging lens (*f*_{2} =
−28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 22.1
cm to the left of the diverging lens. How far is the object from
the converging lens?

Answer #1

f2 = -28 cm

v =-22.1

u = vf/ (v-f) = (22.1*28) / (-22.1+28) = 104.88 cm to the left of
the diverging lens

-------------------------

The distance between the two lenses is 56cm

Therefore v fot the converging lens is to the left of that by a
distance

= 56-104.88 = -48.88 cm

for the converging lens

v = -48.88 cm

f = 24 cm

u = vf/ (v-f) = -48.88 * 24/ (-48.88 - 24) = 16.1 cm

The object is at a distance of 16.1 cm to the left of the
converging lens.

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 21.1 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
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A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
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two-lens combination lies 20.0 cm to the left of the diverging
lens. How far is the object from the converging lens?

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
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