Question

1. If a particle at rest has a mass of 2.54x10^-4 kg and charge 2.70x10^-6 C has an acceleration of 7.23x10³ m/s², how far will it go in 2.0 s? (Note: there is information supplied here that you don't need to solve this problem!)

		14,500 m
		73,500 m
		7,810 m
		390 m

2.

What will the direction of the force on a positive charge at the origin be if there is another positive charge at x = +1 m?

		In the positive x direction
		In the negative x direction
		In the positive y direction
		In the negative y direction

3.

What will the direction of the force on a positive charge at the origin be if there is another positive charge at x = +1 m and a negative charge at y = +1 m?

		northeast
		northwest
		southeast
		southwest

4.

1. If the distance between two charges doubles, what happens to the force between them?

   		It also doubles.
   		It goes up by a factor of four.
   		It goes down by a factor of two.
   		It goes down by a factor of four.

Answer 1

1.

using 2nd equation of motion

d = 0.5 at^2

d = 0.5* 7.23* 1000* 2^2

d = 14500 m

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2.

along - x axis

option (b) is correct

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3.

directed along south-west

option (d) is correct

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4.

F = k q^2 / r^2

since force is inversely proportional to square of the distance between the charges, hence on increasing the distance by factor of 2 will decreases the force by factor of 4

option (d) is correct

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