Question

a) An object is 24 cm to the left of a lens with a focal length of 12 cm. Where is the image, and is it real or virtual? b) We now add two more elements to the problem, a screen and a second lens. The screen is 48 cm to the right of first lens (the one with f=12 cm). The second lens has a focal length of 6 cm, and is to be placed between the image formed by the first lens and the screen so that the image from the second lens falls on the screen. Where (how many centimeters from the first lens) must we place to second lens for this to happen? c) What is the total magnification, and is the final image upright or inverted?

Answer 1

Here we have used the lens formula and the formula for magnification , the most important thing is to take signs correctly