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A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s...

A fish swimming in a horizontal plane has velocity i = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is i = (16.0 − 1.80 ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (23.0 − 1.00 ) m/s.

(a) What are the components of the acceleration of the fish?

ax =

m/s2

ay =

Review the definition of average acceleration and remember that each component is treated separately. m/s2

(b) What is the direction of its acceleration with respect to unit vector ?

° counterclockwise from the +x-axis

(c) If the fish maintains constant acceleration, where is it at t = 26.0 s?

x =

m

y =

m

In what direction is it moving?

° counterclockwise from the +x-axis

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