A fish swimming in a horizontal plane has velocity _{i} = (4.00 + 1.00 ) m/s at a point in the ocean where the position relative to a certain rock is _{i} = (16.0 − 1.80 ) m. After the fish swims with constant acceleration for 17.0 s, its velocity is = (23.0 − 1.00 ) m/s.
(a) What are the components of the acceleration of the fish?
a_{x} = |
m/s^{2} |
a_{y} = |
Review the definition of average acceleration and remember that each component is treated separately. m/s^{2} |
(b) What is the direction of its acceleration with respect to unit vector ?
° counterclockwise from the +x-axis
(c) If the fish maintains constant acceleration, where is it at t = 26.0 s?
x = |
m |
y = |
m |
In what direction is it moving?
° counterclockwise from the +x-axis
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