A satellite is in a circular orbit about the earth (ME = 5.98 x 1024 kg). The period of the satellite is 1.04 x 104 s. What is the speed at which the satellite travels
we know the formula
F=GMm/r2................1)
force that is helping in circular motion of the satellite around the earth is centripetal force
so F=mv2/r........2)
equating both the equations we get
GMm/r2=mv2/r
v2=GM/r.........3)
we know that speed=distance/time
here s= circumference=2pir and time=T
v=2pir/T
r=Tv/2pi
substituting the value of r in eqn 3
v2=2piGM/Tv
v3=2piGM/T
v===6.22*103m/s
so answer is 6.22*103m/s. ( if this is incorrect try 6223m/s or 6222 m/s or 6.223*103 m/s or 6.222*103m/s)
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