Question

While riding in a hot air balloon, which is steadily descending at a speed of 1.34 m/s, you accidentally drop your cell phone.

(a) After 4.00 s, what is the speed of the cell phone?

v

=

m/s

(b) How far is the cell phone below the balloon after this time?

d

=

83.84 Note that the balloon continues to move downward; to find the distance below the balloon at this time, you must take into account both the balloon's motion and the phone's motion. If you know the initial velocity, acceleration, and time, how can you find the distance the cell phone falls, assuming a constant acceleration? Also, be careful of sign. Even though the displacement is in the downward direction, report distance below balloon as a positive number. m

(c) What are your answers to parts (a) and (b) if the balloon is rising steadily at 1.34 m/s?

v	=	m/s
d	=	The analysis is the same as in parts (a) and (b), only now the balloon is moving upward. How will that affect the distance between the balloon and phone at the later time? m

Answer 1