Question

Consider a reaction between 1.2 mol of dicarboxylic acid, 0.9 mol of a diol and 0.2...

Consider a reaction between 1.2 mol of dicarboxylic acid, 0.9 mol of a diol and 0.2 mol of triol to produce a polyamide. a) what is the reactant ratio (r)? Is the reaction in stoichiometric balance?

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Answer #1

1 mol of Polyamide is produced by 1 mol of dicarboxylic acid and 1 mol of diamine ( diamine is not given in the problem)

1 mol of Polyester is produced by 1 mol of dicarboxylic acid and 1 mol of diol.

Stoichiometric Reactants ratio of dicarboxylic acid and diol

= 1/1 = 1

Moles of diol (0.9 mol) < moles of dicarboxylic acid(1.2 mol)

diol is limiting reactant

Moles of Polyester produced = 0.9 mol

Reactant ratio diol and dicarboxylic acid = 0.9/1.2 = 0.75

Reaction is not in stoichiometric balance.

dicarboxylic acid is excess reactant.

Moles of dicarboxylic acid remain after the reaction

= 1.2 - 0.9

= 0.3

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