There is to calculate the concentration of this solution in mol/L
C=n/V=mol/L
The data are
Bromide = 1500 mg =1.5 gram
volume= 1 L
The problem gives the Volume there is to find the number of moles,n
n from the stochiometry of molarity is equal to
n=m/M
where m is the mass in g and M the molecular weight .
we have m,we must calculate M for Br2
The periodic table provides the info
MBr=79.904
The formula is Br =79.904 amu
n=m/M
=1.5/79.904=0.0188 moles
Finally the concentration will be given after volume in L
C=n/V =0.0188/1 =0.0188 mol/L
Get Answers For Free
Most questions answered within 1 hours.