Question

The energy for vacancy formation in Al is 0.66 eV. Calculate the number of vacancies in...

The energy for vacancy formation in Al is 0.66 eV. Calculate the number of vacancies in a 1 cm3 of Al at 300°C and 600°C

Engineering   Chemical-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium...
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 476oC is 3.61E+23 m-3. The density and atomic weight for this metal are 20.1 g/cm3 and 92.40 g/mol, respectively.
Calculate the temperature where the number of vacancies per cubic meter in iron will be 9.40...
Calculate the temperature where the number of vacancies per cubic meter in iron will be 9.40 x 1017 atoms/cm3. The energy for vacancy formation is 1.08 eV/atom.
(a) Calculate the activation energy, QV, for vacancy formation in silver, given that the equilibrium number...
(a) Calculate the activation energy, QV, for vacancy formation in silver, given that the equilibrium number of vacancies at 1073°K is 3.6 x 1023 m-3. The atomic weight and density (at 1073°K) of silver are, respectively, 107.9 g/mol and 9.5 g/cm3 . (b) Suppose that CaO is added as an impurity to Li2O. If the Ca2+ substitutes for Li+ , what kind of vacancies would you expect to form? How many of these vacancies are created for every Ca2+ added?
Consider a metal with an energy for vacancy formation of (6.0000x10^-1) eV/atom. If the material is...
Consider a metal with an energy for vacancy formation of (6.0000x10^-1) eV/atom. If the material is originally at (1.00x10^3) K, calculate the temperature rise (in K) needed to increase the vacancy fraction by a factor of (8.0000x10^0) . Note: Do not enter the resulting temperature, just the change in temperature.
Calculate the equilibrium number of vacancies per cubic meter in gold(Au) at 25(celcius). For gold, the...
Calculate the equilibrium number of vacancies per cubic meter in gold(Au) at 25(celcius). For gold, the energy for vacancy formation is 0.98 eV/atom. Furthermore, the atomic mass and the theoretical density for gold are 196.9 g/mol and 19.32 g/cm^3(at 25 celcius), respectively.
Given that for a typical metal the energy for vacancy formation is on the order of...
Given that for a typical metal the energy for vacancy formation is on the order of 1 eV/atom, melting point is 10^3 K, molar mass is 10^2 g/mol and density is 10 g/cm3. 1.) Near melting point the fraction of vacant lattice sites is: a) <10^-5 b) 10^-5 to 10^-3 c) 10^-3 to 10^-2 d) 10^-2 to 10^-1 2.) The number of vacant sites per cm^3 is typically: a) <10^3 b)10^3 to 10^6 c) 10^6 to 10^9 d) > 10^9...
The energy of formation of Schottky defects in a crystal of CaO is given as 6.1...
The energy of formation of Schottky defects in a crystal of CaO is given as 6.1 eV. Calculate the number of Schottky defects present in CaO at 1000 oC and 2000 oC. How many vacancies are present at these temperatures? CaO has a density of 3300 kg*m-3.
Compute the concentration (number density, count per volume) of vacancies in copper at room temperature if...
Compute the concentration (number density, count per volume) of vacancies in copper at room temperature if the lattice parameter of FCC copper is 0.3615 nm at room temperature (25oC, 298 K), and the activation energy to form a single vacancy is 0.9 eV. Use 8.617x10-5 eV/(atom-K), exactly, as Boltzmann's Constant. Note: You could look up the density and atomic weight of copper to compute the intermediate value of atom concentration you need for this problem. But here I give you...
The concentration of vacancies in niobium (Nb) at 765˚C is 9.836 x 1018 cm-3. If niobium...
The concentration of vacancies in niobium (Nb) at 765˚C is 9.836 x 1018 cm-3. If niobium has a BCC crystal structure and a lattice parameter of 0.3302 nm, calculate the energy for vacancy formation in niobium.
Why do vacancies and interstitials have a positive energy of formation? Why are they present at...
Why do vacancies and interstitials have a positive energy of formation? Why are they present at finite temperatures if they’re not energetically favored?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT