Question

Calculate the pH of the following hydrochloric acid (HCl) solutions. Assume that HCl is completely dissociated into hydrogen ion (H+) and chloride ion (Cl-) in water.

(a) 10-2 M, 10-3 M, 10-4 M, 10-5 M, 10-6 M, 10-7 M, 10-8 M, 10-9 M

(b) Draw a plot of pH as a function of HCl concentrations based on the solutions of (a)

Answer #1

SOLUTION :

REACTION

SO FOR DIFFERENT MOLARITY CONCENTRATION;

1) WHEN [HCl] = 10^-2 M

[H+] = 10^-2 M

PH = - log[H+]

PH = - log[10^-2]

PH= 2

SIMILLARALY FOR DIFFERENT CONCENTREATION WE GET PH VALUE GIVEN BELOW

MOLARITY | PH |

0.01 | 2 |

0.001 | 3 |

0.0001 | 4 |

0.00001 | 5 |

0.000001 | 6 |

0.0000001 | 7 |

0.00000001 | 8 |

0.000000001 | 9 |

NOW WE DRAW THE GRAPH OF PH AS A FUNCTION OF CONCENTRATION OF HCL(OR H+ OR Cl-)

PH VS CONCENTRATION

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