Question

Calculate the pH of the following hydrochloric acid (HCl) solutions. Assume that HCl is completely dissociated into hydrogen ion (H+) and chloride ion (Cl-) in water.

(a) 10-2 M, 10-3 M, 10-4 M, 10-5 M, 10-6 M, 10-7 M, 10-8 M, 10-9 M

(b) Draw a plot of pH as a function of HCl concentrations based on the solutions of (a)

Answer 1

SOLUTION :

REACTION

SO FOR DIFFERENT MOLARITY CONCENTRATION;

1) WHEN [HCl] = 10^-2 M

[H+] = 10^-2 M

PH = - log[H+]

PH = - log[10^-2]

PH= 2

SIMILLARALY FOR DIFFERENT CONCENTREATION WE GET PH VALUE GIVEN BELOW

MOLARITY	PH
0.01	2
0.001	3
0.0001	4
0.00001	5
0.000001	6
0.0000001	7
0.00000001	8
0.000000001	9

NOW WE DRAW THE GRAPH OF PH AS A FUNCTION OF CONCENTRATION OF HCL(OR H+ OR Cl-)

PH VS CONCENTRATION