A rigid container of volume 0.2 m3 contains 5 kg of water at 20 ◦C. The maximum allowable pressure of the container is set at 10 MPa. The system is now connected to a heat source, which transfers heat at a rate of 1000 W to the container. How long will the container survive?
Since the container is rigid the specific volume will remain unchanged
Specific volume (V) =0.2/5 = 0.04 m3/Kg
Now we will look up in steam table and find the value of enthalp corresponding to the above value of secific volume and Pressure of 10 MPa
T = 630 oC and H=3699.43 KJ/Kg
Total enthalpy = 3699.43*5 =18497 KJ = 18497150 Joule
Let the time which the container cam survive be "t" second
Hence energy supplied till the point where container breaks will be
1000*t =18497150
t =18497.15 seconds =308.285mins =5.138 hours
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