Question

An adiabatic reversible pump is designed to take saturated water at 0.01 MPa and compress it...

An adiabatic reversible pump is designed to take saturated water at 0.01 MPa and compress it to 3.5 MPa. What is the change in enthalpy of the water?
(Answer in kJ/kg)

What is enthalpy of the water exiting the pump?
(Answer in kJ/kg)

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Homework Answers

Answer #1

we will make use of steam table to solve our problem

state 1: Saturated vapor at T = MPa

T =45.80 oC

H = 2583.8869 KJ/Kg

Gamma = 1.3

Change in enthalpy for an adiabatic for a reversible process

W = 25256.23 KJ/Kg

W= H2-H1

25256.23 =H2- 2583.8869

enthalpy of water exiting the pump

H2 = 22672.347 KJ/Kg

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