Question

1. Predict how the addition of hydrochloric acid to Ca(OH)₂ (s) would affect the equilibrium in Part one of your experiment. Explain your prediction in terms of Le Chetalier's principle. Why would HCl react with Ca(OH)₂? Show the reaction(s)

2. Indicators are usually organic molecules with functional groups that will accept protons. This will change the structure and make the molecule change color. Why are these values not included in acid/base equilibrium?

3. Lead (II) chloride (PbCl₂) is a white solid. For the equilibrium reaction: PbCl₂(s) = Pb+2(aq) + 2Cl‐(aq)

The Ksp for PbCl₂ = 1.6 * 10‐5. At equilibrium, would you expect to have more lead and chloride ions or more solid lead (II) chloride? Explain.

Answer 1

Answer to Question 1

Reaction between Ca(OH)2 AND HCl is as follow

Now we will apply Le Chatelier's principle. Here we are adding HCl which is a reactant. As per the principle on adding a compound at equilibrium the equilibrium will move in a direction to negate the effect brought in the system. Now since HCl is added in the system it will want to negate it ,i.e, it will react more of HCl as it is added and this will result in more amount of Product that is CaCl2 and H20