initially contains steam at
Pressure P = 1 bar
Temperature T = 150℃
At initial conditions
Specific volume = 1.9364 m3/kg
Specific internal energy = 2582.8 kJ/kg
Initial mass = initial volume / Specific volume
= 1 m3 / 1.9364 m3/kg
= 0.5164 kg
From the mass balance equation
M2 = M1 + Msteam
From the energy balance equation
Assume the different values of T2
V2' = V2 /M2
Difference between V2' & V should be less than 3%
For trials and error, we get T2 = 425°C
Pressure P2 = 5 bar
Final conditions
Specific internal energy = 3004.5 kJ/kg
Specific volume = 0.6407 kg/m3
Mass of steam = 1.0628 kg
M2 = 1.56 kg
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