Question

A mixture of Mol-100 kmol containing 70% benzene and 30% toluene must be separated at a...

A mixture of Mol-100 kmol containing 70% benzene and 30% toluene must be separated at a total pressure of 101.325 KPA (1 atm). A differential distillation column and an equilibrium(flash) distillation column are available in the enterprise to perform this operation. If 45 kmol distillate (top product) is obtained; a -) the composition of the distillate and remaining liquid obtained by differential distillation, B -) determine the composition of distillate and liquid obtained from equilibrium distillation. What distillation process would you recommend? Please explain. Data: benzene vapor pressure (KPa) 101.325 Temperature 80.1 °C Mole fraction of benzene in liquid, xa 1.00 Mole fraction of benzene steaming, or 1.00 Vapor pressure of toluene (kPa), 101.325

Data:
Benzemez vapor pressure(KPa) 101.325
Tempeture 80.1 °C
Mole fraction of benzene in liquid, da 1.00
Mole fraction of benzene steaming, or 1.00
Vapor pressure of toluene(KPa), 101.325

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Answer #1

Differential process is recommended as more effective separation can be achieved (more benzene in distillate and more toluene in bottom product) as compared to Equilibrium process.

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