Benzene and Toluene are in a solution at equilibrium with the following conditions: T=25oC and XB=.500. Calculate the composition of Benzene in the vapor phase
Vapour pressure of pure benzene and toluene are 95.1 and 28.4 mm Hg respectively
according to Raoult’s law
PA = PA0XA
PA = partial pressure of A
PA0 = vapour pressure of pure A
XA = mole fraction in liquid of component A
Total pressue P = PA + PB
if there is only two component in solution XA + XB = 1
XB = 1-XA
Ptotal = 95.91 mmHg x Xbenzene + 28.4 mmHg x (1-Xbenzene)
= 95.91 x 0.5 + 28.4 x (1-.5)
= 62.155 mm Hg
Ybenzene = Pbenzene/Ptotal
= 95.91 x 0.5 / 62.155 = 0.77 ans
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