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Consider a cell at steady state. The intracellular Cl- concentration is 10 mM, while the extracellular...

Consider a cell at steady state. The intracellular Cl- concentration is 10 mM, while the extracellular Cl- concentration is 108 mM when the chloride channels are closed. The electrical potential inside the cell is -65 mV, and the external potential is 0 mV. Calculate the electrochemical potential difference across the membrane. Assume R = 8.3144 J/mol K and T = 37C. When the chloride channels open, in which direction will the Cl- ions move?

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Answer #1

ELECTROCHEMICAL POTENTIAL DIFFERENCE ACROSS MEMBRANE=

R =8.3144 J/mol/K

T (KELVIN) = 37 (IN CELSIUS)+273.15= 310.15K

z= valence of the ionic species, IN THIS EQUATION FOR CHLORIDE ION IT IS -1

F= 96,485 C.mol−1

KO = EXTRACELLULAR CONCENTRATION OF CHLORIDE ION

KI = INTRACELLULAR CONCENTRATION OF CHLORIDE ION

Putting the values in equation,

=

= -0.064V

When the chloride channels open, Cl-1 moves from outside of cell to inside the cell because it follows the concentration gradient in which ions move from higher to lower concentration area.

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