Question

Give out for the quantum numbers (n, l, ml, ms) for electrons of the highest energy in Ne atom.

Answer 1

Atomic number of Ne = 10

Electronic configuration of Ne = [He] 2s2 2p6

Highest energy is 2p subshell

Principal quantum number n = 2

Angular momentum quantum number l = 0 to n-1

l = 0 to 1

l = 0 - - - - > s-subshell

l = 1 - - - - - > p-subshell

For the p-subshell, l = 1

Magnetic quantum number ml = - l to +l

ml = - 1, 0, +1

p-subshell has 6 electrons

ml = - 1 - - - - - - > 2px orbital

ml = 0 - - - - - - > 2py orbital

ml = +1 - - - - - - > 2pz orbital

spin quantum number

ms, have two possible values = ±1/2

For 6 electrons in the highest energy p-subshell

n = 5, l = 1, ml = - 1, ms = +1/2

n = 5, l = 1, ml = - 1, ms = - 1/2

n = 5, l = 1, ml = 0, ms = +1/2

n = 5, l = 1, ml = 0, ms = - 1/2

n = 5, l = 1, ml = + 1, ms = +1/2

n = 5, l = 1, ml = + 1, ms = - 1/2