Saturated liquid water at 60 bar is heated until the quality is 43%.
Calculate the amount of heat (kJ/kg) that needs to add into the system.
Saturated liquid water at 60 bar. From steam table following properties can be found:
v1 = 0.001319 m3/kg h1 = 1213.32 kJ/kg, T1 = 275.64 oC
Now this sytem is heated utill the quality is 43%
State 2: P2 = 60 bar, T2 = 275.64 oC and x = 0.43
h2 =(1-x)hl+xhv = (0.57 x 1213.32)+(0.43 x 2784.33) = 1888.85 kJ/kg
Since the process is a constant pressure process, the heat transfer will be equalt to change in enthalpy, thus
Q = h2 - h1 = 1888.85 - 1213.32 = 675.53 kJ/kg
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