Question

Consider the following reaction at 298K.
I2 (s) + Sn (s) 2 I- (aq) + Sn2+ (aq)

Which of the following statements are correct?

Choose all that apply.
?Go < 0
The reaction is reactant-favored.
n = 2 mol electrons
K > 1
Eocell < 0

Answer 1

The given reaction

I2 (s) + Sn (s) = 2 I- (aq) + Sn2+ (aq)

The two half cell reactions are

Reduction reaction

I2 (s) + 2e- = 2 I- (aq)

Ered = 0.54 V

Oxidation reaction

Sn (s) = Sn2+ (aq) + 2e-

Eox = 0.14 V

Standard reduction potential

E°cell = Eox + Ered

= 0.14 + 0.54

= 0.68 V

E°cell > 0

n = 2 mol electrons

G°= - nFE°cell

= - 2 x 96500 x 0.68

= - 131240 J

G° < 0

K = exp (-G°/RT)

= exp (131240/8.314 * 298)

= 1.01 x 10^23

K > 1

Reaction is product favored.