Question

At what pressure is liquid n-hexane in equilibrium with its vapour at 450K?

Answer #1

the pressure we have to find is the vapor pressure at 450K.

Vapor Pressure of a liquid is defined as the equilibrium pressure exerted by vapor with the liquid at the given temperature.

Here we have n-hexane at 450K.

This can be estimated with the use of Antoine equation.

P^{sat} is in torr or mmHg

T is in ^{o}C = 450-273.15=176.85^{o}C

Antoine constants for n-hexane for given temperature.

A=7.01051

B=1246.33

C=232.988

Solving gives,

760mmHg = 1 atm = 101325 Pa

Thus our answer is 1242.75 kPa.

Hope this is clear for you.

feel free to ask if having any doubts.

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