It is desired to sample a nuclear power plant coolant system. The coolant contains N-16 radioactivity of 3 mCi/ml . It is desired to put a piping system that will delay the sample to allow the N-16 to decay to a level of 1 microcurie per ml. The velocity of the fluid in the pipe is 3 ft/s.
What is the minimum length of pipe required?
The half life of N16 = 7.13 s
now calculate the number of half life
assume initial concentration is CA0 = 3 mCi /ml=
3*10-3 Ci/ml
assume there is after n half life concentration is CA = 1 micro curi / ml = 10-6 Ci/ ml
CA =( CA0/2)n
substitute all the values in above expression
10-6 Ci/ml = ( 3*10-3 Ci/ml )n
take the ln of above expression and solve
n = 2.38
half life of N16 = 7.13 s
total time = 7.13 s * 2.38 = 16.9694 s
length of the pipe = velocity * time = 3 ft/s *16.9694 s = 50.9 ft
length of pipe= 50.9 ft
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