Acetylene is hyrodgenated to form ethane. The feed to the
reactor contains 1.30 mol H2/mol
C2H2. The reaction proceeds to
completion.
a. Calculate the stoichiometric reactant ratio (mol H2
reacted/mol C2H2 reacted) and the yield ratio
(mol C2H6 formed/mol H2
reacted).
b. Determine the percentage by which acetylene is in excess.
c. Calculate the mass feed rate of hydrogen (kg/s) required to
produce 4.00 x 106 metric tons of ethane per year,
assuming that the reaction goes to completion and that the process
operates for 24 hours a day, 300 days a year.
The balanced reaction
C2H2 + 2H2 => C2H6
In the feed
Mol H2 / mol C2H2 = 1.30
Part a
stoichiometric reactant ratio
mol H2 reacted/mol C2H2 reacted = 2
yield ratio
mol C2H6 formed/mol H2 reacted = 1/2 = 0.50
Part b
From the stoichiometry of the reaction
2 mol H2 required = 1 mol C2H2
1.30 mol H2 required = 1.30/2 = 0.65 mol C2H2
Excess reactant = C2H2
% C2H2 in excess = (1 - 0.65)*100/1 = 35%
Part c
mass feed rate of hydrogen =?
Ethane formed = 4*10^6 MT/year
30 MT ethane formed from = 4 MT H2
4*10^6 MT/year ethane formed from = 4*4*10^6/30 = 5.33*10^5 MT/year H2
Mass of H2 required
= 5.33*10^5 MT/year x 1000kg/MT x 1year/300days x 1day/24hr x 1hr/3600s
= 20.576 kg/s
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