Ans 1
The first reaction is
2Fe(s) + 6HF(g) —> 2FeF3(s) + 3H2(g)
multiply by 0.5
Fe(s) + 3HF(g) —> FeF3(s) + 1.5H2(g)
H1 = -1787.4*0.5 = - 893.7 kJ/mol
The second reaction is
2Fe(s) + 6HCl(g) —> 2FeCl3(s) + 3H2(g)
Reverse the reaction and multiply by 0.5
FeCl3(s) + 1.5H2(g) = Fe(s) + 3HCl(g)
H2 = 1457.0*0.5 = 728.5 kJ/mol
Add the two reactions
Fe(s) + 3HF(g) + FeCl3(s) + 1.5H2(g) —> FeF3(s) + 1.5H2(g) + Fe(s) + 3HCl(g)
FeCl3(s) + 3HF(g) —> FeF3(s) + 3HCl(g)
H = H1 + H2
= - 893.7 + 728.5
= - 165.2 kJ/mol
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