Question

A 300km mass of water with temperature 50 C is mixed with 20kg of ice, The...

A 300km mass of water with temperature 50 C is mixed with 20kg of ice, The mixture has final temperature of 40C. What is initial temperature of ice ?

Latent heat of evaporation of water at 101.3 kPa is ?

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Answer #1

Mass of water mw = 300 kg

Specific heat capacity of water Cpw = 4184 J/kg-C

Temperature of water Tw = 50 C

Final temperature T = 40 C

Heat released by water Q = mw x Cpw x (Tw - T)

= 300 kg x 4184 J/kg-C x (50 - 40)C

= 12552000 J

Heat absorbed by ice

Q = mi x Cpi x (T - Ti) + mi x latent heat of fusion

12552000 J = 20 kg x 2108 J/kg-C x (40 - Ti) + 20 kg x 333000 J/kg

5892000 = 42160 (40 - Ti)

40 - Ti = 139.75

Ti = - 99.75 C

Latent heat of evaporation of water at 101.3 kPa

= 2256 kJ/kg

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