A 300km mass of water with temperature 50 C is mixed with 20kg of ice, The mixture has final temperature of 40C. What is initial temperature of ice ?
Latent heat of evaporation of water at 101.3 kPa is ?
Mass of water mw = 300 kg
Specific heat capacity of water Cpw = 4184 J/kg-C
Temperature of water Tw = 50 C
Final temperature T = 40 C
Heat released by water Q = mw x Cpw x (Tw - T)
= 300 kg x 4184 J/kg-C x (50 - 40)C
= 12552000 J
Heat absorbed by ice
Q = mi x Cpi x (T - Ti) + mi x latent heat of fusion
12552000 J = 20 kg x 2108 J/kg-C x (40 - Ti) + 20 kg x 333000 J/kg
5892000 = 42160 (40 - Ti)
40 - Ti = 139.75
Ti = - 99.75 C
Latent heat of evaporation of water at 101.3 kPa
= 2256 kJ/kg
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