Question

Calculate the rate of cooling (kW) required to bring 300kg/min of carbon monoxide from 450°C to 50°C, performing the calculation in two ways:

a. Using the CP of CO:

CP(kJ/(mol°C)) = 28.95*(10^-3) + 0.411*(10^-5)T + 0.3548*(10^-8)(T^2) - 2.22*(10^-12)(T^3)

b.Using tabulated data:

H(CO, 50°C, 1atm) = 0.73kJ/mol

H(CO, 450°C, 1atm) = 12.82 kJ/mol

The reference state for these values is CO gas at 1atm and 25°C

Answer 1