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A humid air stream enters a process at 35 C, 20 atm, and 50% relative humidity....

A humid air stream enters a process at 35 C, 20 atm, and 50% relative humidity. The oxygen flows at 900kmol/h. Determine the molar flow rate of water in the stream.
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Answer #1

Oxygen flow rate = 900 kmol/h.

As air contains 21% oxygen by mole, tha flow rate of air = 4285.7 kmol/h

Relative humidity, RH = 50/100 = 0.50 = Partial pressure of water / vapor pressure of water at given temp

As at 35 C, tha vapor pressure of water is = 5.628 kPa

Partial pressure of water = 0.50 x 5.628 = 2.7814 kPa

Mole fraction of water in air , ywater = Partial pressure / total pressure

ywater = 2.7814/(20x101.325) = 0.00139

Molar flow rate of water in stream = mole fraction of water in air x Molar flow rate of air = 0.00139 x 4285.7 kmol/h

Molar flow rate of water in stream = 5.9511 kmol/hr.

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