Question

Given the following : weight of dry sample in air = 64 g,

weight of dry sample coated with paraffin =66g.

weight of coated sample in brine = 42.0 g.

Find the bulk volume, pore volume, and grain volume. find porosity, sample density .

Find original volume of oil and gas in place ( A= 320acres, H = 120 ft).

How much oil and how much gas can be recovered? Is this system oil wet or gas wet?

Answer 1

SOLUTION:

The drop in weight due to immersion in brine is (66.0-42.0) g = 24.0 g.

Specifid Gravity of Brine is 1.05 g/cc.

So, volume of displaced brine is (24.0 / 1.05) cc = 22.85 cc.

Volume of the Paraffin coat is {(66.0-64.0)/0.85} cc = 2.35 cc.

Hence the Bulk Volume of the sample is (22.85-2.35) cc = 20.5 cc.

Grain volume is calculated as Weight / Grain density = {64.0 g / (2.65 g/cc)} = 24.15 cc.

Pore Volume is (Bulk Volume- Grain volume) = (24.15-20.5) cc = 3.65 cc.

Porosity is calculated as

    phi=(Vp/Vb)*100 =(3.65/20.5)*100= 17.80

Sample Density is calculated as Weight/Bulk Volume = 64.0 g / 24.15 cc = 2.65 g/cc.

Rock Type is Quartz.