Question

Given the following : weight of dry sample in air = 64 g,

weight of dry sample coated with paraffin =66g.

weight of coated sample in brine = 42.0 g.

Find the bulk volume, pore volume, and grain volume. find porosity, sample density .

Find original volume of oil and gas in place ( A= 320acres, H = 120 ft).

How much oil and how much gas can be recovered? Is this system oil wet or gas wet?

Answer #1

**SOLUTION:**

**The drop in weight due to immersion in brine is
(66.0-42.0) g = 24.0 g.**

**Specifid Gravity of Brine is 1.05 g/cc.**

**So, volume of displaced brine is (24.0 / 1.05) cc =
22.85 cc.**

**Volume of the Paraffin coat is {(66.0-64.0)/0.85} cc =
2.35 cc.**

**Hence the Bulk Volume of the sample is (22.85-2.35) cc =
20.5 cc.**

**Grain volume is calculated as Weight / Grain density =
{64.0 g / (2.65 g/cc)} = 24.15 cc.**

**Pore Volume is (Bulk Volume- Grain volume) =
(24.15-20.5) cc = 3.65 cc.**

**Porosity is calculated as**

** phi=(Vp/Vb)*100 =(3.65/20.5)*100=
17.80**

**Sample Density is calculated as Weight/Bulk Volume =
64.0 g / 24.15 cc = 2.65 g/cc.**

**Rock Type is Quartz.**

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