Question

Chlorobenzene (density of 1109 kg / m^{3}) and an aqueous
washing liquid (density of 1020 kg / m^{3}) are separated
in a tubular centrifuge with an internal diameter of 150 mm which
rotates at 8000 r / min. The free surface of the liquid inside the
container is 40 mm of the axis of rotation. If the centrifuge
contains equal volumes of the two liquids,

What will be the radial distance from the axis of rotation to the top of the spill zone of the heavy liquid?

Answer #1

**Solution:**

**The computation are as expressed below,**

**D2 = 150 mm, r2 = 75 mm, w = 8000 rpm, rB = 40 mm, [pB]
= 1109 kg/m3, [pA] = 1020 kg/m3,**

**a) radial distance is,**

**plugging values and solving for rA we get**

**rA = [(75^2*(1-1020/1109)) +
((1020/1109)*40^2]0.5**

**= 43.852 mm**

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