Question

A reactor with a volume of 2.50 m3 is filled with catalyst particles (SG = 7.85). The fraction of the volume taken up by the air space between the particles, called the void fraction, is 40.0%. A mixture of 60.0 wt% chloro-benzene and 40 wt% ethyl-chloride is added to the reactor until it fills the void space completely. Estimate the total weight of the liquid and solid in the vessel.

Answer 1

Given total volume of the reactor=2.5 m³

Out of which 40 % is void fraction and completely filled with Liquid mixture of Chloro-benzene and ethyl chloride.

Remaining 60% is solid catalyst.

Total solid weight can be estimated as,

SG= 7.85 implies its density is 7.85*10³ kg/m³

Volume = 0.6 * 2.5 m³

Thus weight, = volume * density = 2.5*0.6*7.85*10³ = 11775 kg

Now remaining 40% of 2.5 m³ is liquid having composition of 60 wt% chloro-benzene and 40 wt% ethyl chloride.

ie., .4*2.5=1 m³ is the volume of liquid.

For 1 kg liquid, 0.6 kg chlorobenzene and 0.4 kg ethyl chloride is present.

Density of chlorobenzene is 1.11 *10³ kg/m³

Density of ethyl chloride is 920 kg/m³

Thus volume of 1 kg liquid is

so weight of 1 m³ of liquid is   

Hope this is clear for you. feel free to ask if having any doubts.

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