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The boiling point of liquid nitrogen at 1 atm pressure (NBP) is -195.8°C. Liquid nitrogen stored...

The boiling point of liquid nitrogen at 1 atm pressure (NBP) is -195.8°C. Liquid nitrogen stored in an insulated vessel at 1 atm (abs) evaporates and the nitrogen vapour is compressed to 50 atm (abs) and heated to a temperature of 70°C at the rate of 5.5 kg/min. What is the volumetric flowrate of the gas from the heat exchanger?  

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Answer #1

Initial pressure Pi=1 atm;, and initail boiling point= -195.8°C=273-195.8= 77.2K

GIven vapor mass flowrate m=5.5kg/min, at boiling point 70°C, Pf=50atm

so we need to find density of the evaporating gas at the Final evaporating temperature from the following formula.

P=50atm=50*101325Pa=5066250Pa

R=8.314 KJ/(Kmol.K)

T=70+273=343K

M=28Kg/Kmol

Substituing all the paramters in the equation gives

= (5066250Pa*28Kg/Kmol)/(8.314K J/(Kmol.K)*343K)

=49.74Kg/m3

so volumetric flowrate would be v=m/

=(5.5Kg/min)/(49.74Kg/m3)

=0.110m3/min=110L/min

So final volumetric fowrate would be 110L/min

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