Write 4 quantum numbers in sequence for
a) the last electron of Al
b) for last electron of Ca
c)the 50th electron of W
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a)Al is located in group 3 tells you that it has 3 valence electrons. The first valence electron is added to the 3p orbital when the orbital is empty, so we assign it a positive spin, or m2=+12.
This means that you have
n=3
l=1
m=?1
s=+1/2
b)calcium is located in group 2 tells that it has 2 valence electrons. The first valence electron is added to the 4s orbital when the orbital is empty, so we assign it a positive spin, or m=+1/2.
This implies that the second valence electron that is added to the 4s orbital will have a negative spin, ms=?1/2.
This means that you have
n=4,l=0,ml=0,ms+?12
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