The exhaust products from complete combustion of 1 kmol of PROPANE GAS contain 3 kmol of CO2, 4 kmol of H2O , 1 kmol of O2 and 22.56 kmol of N2 gases. Water vapor will begin to condense into liquid as the exhaust gases are cooled below (????) degrees C. Enter a integer value.
Let us first obtain the mole fraction of Water
Total moles = 3+4+1+22.56 = 30.56 kmol
Mole fraction of water (Ywater) = 4/30.56 =0.13
Now let us assume that the outlet is at atmospheric pressure
Partial pressure of water = Yi*P = 0.13*1 = 0.13 atm = 98.8 mmHg
Now we will make use of Antoine equation to solve this problem
Where P is in mmHg and T is in oC
substituting P = 98.8 mmHg in above equation to get T
T =51.40 oC
?Hence the temperature at which the water vapor will start condensing is 51 oC
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