Question

In the experiment, you performed the reaction below. (You added 5 ml of 0.40 M NaOH in methanol to 20 mL of cooking oil.)

The density of cooking oil is 0.895 g/mL and its molar mass is 885.43 g/mol. The formula for glycerol is C3H8O3. The density of cooking oil is 0.895 g/mL and its molar mass is 885.43 g/mol.

How many moles of cooking oil are in 20 mL of cooking oil?

Starting with 20 mL of cooking oil, excess amounts of methanol, and NaOH catalyst. Assuming 100% yield, how many grams of Biodiesel is produced?

Answer 1

Mass of cooking oil = volume x density

= 20 mL x 0.895 g/mL = 17.9 g

Moles = Mass/molar mass

= 17.9/885.43

= 0.0202 mol

The balanced reaction

1 mol oil produces = 1 mol of biodiesel

0.0202 mol oil produces = 0.0202 mol of biodiesel

Mass of biodiesel produced = moles x molecular weight

= 0.0202 mol x 292.2 g/mol

= 5.91 g