Question

The fugacity coefficient of a certain gas at 290K and 3.1MPA is .70. Calculate the difference of its molar Gibbs energy from that of a perfect gas in the same state.

Answer #1

**Given:**
Temperature, T=290 K

Pressure, P= 3.1 MPa

Fugacity Coefficient of gas, =0.70

For an ideal gas, molar Gibbs Energy is given as

For an ideal gas, G_{m}=G^{0}_{m}

where G_{m} is Molar Gibbs Energy

G^{0}_{m} Standard Molar Gibbs Energy

R is Universal Gas Constant, R=8.314 J/mol K

T is the Temperature

p and p^{0} is the Pressure of Gas

For a real gas, the molar Gibbs energy is

where f is the Fugacity of gas

Subtract Equation 2 and Equation 1,

Fugacity coefficient is

Substitute the values

**
the difference of Molar Gibbs Energy of a Gas and that of an Ideal
Gas is G _{m}-G^{0}_{m}= -0.86
kJ/mol**

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