The fugacity coefficient of a certain gas at 290K and 3.1MPA is .70. Calculate the difference of its molar Gibbs energy from that of a perfect gas in the same state.
Given: Temperature, T=290 K
Pressure, P= 3.1 MPa
Fugacity Coefficient of gas, =0.70
For an ideal gas, molar Gibbs Energy is given as
For an ideal gas, Gm=G0m
where Gm is Molar Gibbs Energy
G0m Standard Molar Gibbs Energy
R is Universal Gas Constant, R=8.314 J/mol K
T is the Temperature
p and p0 is the Pressure of Gas
For a real gas, the molar Gibbs energy is
where f is the Fugacity of gas
Subtract Equation 2 and Equation 1,
Fugacity coefficient is
Substitute the values
the difference of Molar Gibbs Energy of a Gas and that of an Ideal Gas is Gm-G0m= -0.86 kJ/mol
Get Answers For Free
Most questions answered within 1 hours.