Question

What is the change in free energy at 298K when 13.2ml of 0.811M calcium chloride is...

What is the change in free energy at 298K when 13.2ml of 0.811M calcium chloride is combined with 85.5ml of 0.854M sodium carbonate? ( R=8.31J/(K * mol))

Ca^2+(aq) + CO3 2-(aq)--->CaCO3(s)

ANSWERS

A. -2.21 X 10^3kJ   

B. -41.2 kJ

C. -46.5 kJ

D. -47.4 kJ

E. 4.04 X 10^3 kJ

(They also put this on my homework to help...)

Substance (delta)G(formation) (kJ/mol) at 298K

Ca^2+(aq) -553.5

CO3^2-(aq) -527.9

CaCO3(s) -1128.8

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