The partial pressure of water at 298 K is 23 mbar in our atmosphere. A thirsty explorer wants to condense water vapour in the air to drink. What is the minimum volume of air he needs to work with to obtain 1 L of water through this process? Remember that the density of water is 1 g/mL.
In this problem, we observe that the amount of water required is 1 litre.
Now, since the number of moles is proportional to the partial pressure in the system i.e.
n p
or, n1/n2 = p1/p2
And the number of moles is also proportional to the volume of gas i.e.
n V
or, n1/n2 = V1/V2
we have,
V1/V2 = p1/p2
or, V1/Vtotal = p1/ptotal
Hence, we need to calculate the value of Vtotal, as we have the value of V1 = 1 litre, p1 = 0.23 bar, ptotal = 1.013 bar (atmospheric pressure = 1.013 x 105 Pa = 1.013 bar)
Hence Vtotal = 1.013 / 0.23 = 4.404 litre. This will be the total volume of air required and the required answer.
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