The following chemical reaction occurs in a reactor:
A + 3B ? 2C
It is known that such process has a conversion of 20% for compound A. The reactor’s feed contains 25 wt% of A and 75 wt% of B, and has a mass flow of 1000 kg/h. The molecular weights for A and B are 28 and 2, respectively.
a) What is the molecular weight of C?
b) What is the composition (in wt%) of the output stream?
mass flow of feed = 1000 kg/h
Mass of A in feed = 1000 x 0.25 = 250 kg/h
Mass of B = 1000 x 0.75 = 750 kg/h
Moles of A = 250/28 = 8.928 kmol
Moles of B = 750/2 = 375 kmol
A is limiting reactant
Moles of A consumed = 8.928*0.20 = 1.7856 kmol
Moles of A remain in the outlet = 7.1424 kmol
Mass of A remain = 7.1424 kmol x 28 kg/kmol
= 199.9872 kg
Moles of B consumed = 3*1.7856 = 5.3568 kmol
Moles of B remain in the outlet = 375 - 5.3568
= 369.6432 kmol
Mass of B remain = 369.6432 kmol x 2 kg/kmol
= 739.2864 kg
Moles of C formed = 2*1.7856 = 3.5712 kmol
Mass of C formed = 1000 - 739.2864 - 199.9872
= 60.7264 kg
Molecular weight of C = 60.7264 kg / 3.5712 kmol
= 17 kg/kmol
Total Mass in outlet = 199.9872 + 739.2864 + 60.7264
= 1000 kg
In the outlet
Mass % A = 199.9872*100/1000 = 19.99% = 20%
Mass % B = 739.2864 *100/1000 = 73.93%
Mass% C = 60.7264*100/1000 = 6.07
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