If a 0.5 L bottle (under
50 bar pressure) of boron trifluoride (BF3) leaks into a 1000m^2
cleanroom, will it be immediately dangerous to health? and why?
Volume of BF3 = 0.5 L
Pressure P = 50 bar
Room temperature T = 27 + 273 = 300 K
From the ideal gas equation
Moles of BF3 = PV/RT
= ( 50 bar x 0.987atm/bar x 0.5 L) / (0.0821 L-atm/mol-K x 300K)
= 1.01 moles
At STP, Volume of BF3 in cleanroom = 1.01 mol x 22.4L/mol
= 22.624 L
Volume of room = height x area
= 3 m x 1000 m2 = 3000 m3 x 1000L/m3
= 3 x 10^6 L
Concentration of BF3 in ppm = 22.624*10^6/(3*10^6)
= 7.5 ppm
Yes it is immediately dangerous to health because it is higher than the threshold limit of 0.05 ppm and 4 times higher the threshold value (2 ppm) is life threatening.
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