Burning H2 (g) in the presence of O2 (g) proceeds by the following reaction:
H2 (g) + ½ O2 (g) --> H2O (g) eq. 1
In a fuel cell, the oxidation half-reaction occurring at the anode (a solid conductor) is:
H2 (g) --> 2H+ (aq) + 2e- eq. 2
At the cathode (solid conductor), O2 is reduced:
O2 (g) + 4H+ (aq) + 4e- --> 2H2O (l) eq. 3
Using Hess’s Law, estimate the heat released by oxidizing 1.0 kg (495 mol) of H2 in a fuel cell. Note that the physical state of water is different in equations 1 and 3. The heat of vaporization () of water is 40.7 kJ/mol. Hint: Start by combining the half reactions and canceling species that appear on both sides.
A. 121.4 MJ |
B. 660.0 J |
C. 141.6 MJ |
D. 161.7 MJ |
Get Answers For Free
Most questions answered within 1 hours.